Showing posts with label equations. Show all posts
Showing posts with label equations. Show all posts

Wednesday, 20 June 2012

The Inverse Z Transform


Given a Z domain function, there are several ways to perform an inverse Z Transform:
The only two of these that we will regularly use are direct computation and partial fraction expansion.

Inverse Z Transform by Long Division

To understand how an inverse Z Transform can be obtained by long division, consider the function
If we perform long division
we can see that
.
So the sequence f[k] is given by
Upon inspection
Note: We already knew this because the form of F(z) is one that we have worked with previously (i.e., the exponential function).

This technique is laborious to do by hand, but can be reduced to an algorithm that can be easily solved by computer.

Inverse Z Transform by Direct Computation

The need for this technique, as well as its implementation, will be made clear when we consider transfer functions in the Z domain.  We will present this method at that time.

Inverse Z Transform by Partial Fraction Expansion

This technique uses Partial Fraction Expansion to split up a complicated fraction into forms that are in the Z Transform table.  If you are unfamiliar with partial fractions, here is an explanation.
As an example consider the function
For reasons that will become obvious soon, we rewrite the fraction before expanding it by dividing the left side of the equation by "z."
Now we can perform a partial fraction expansion
These fractions are not in our table of Z Transforms.  However if we bring the "z" from the denominator of the left side of the equation into the numerator of the right side, we get forms that are in the table of Z Transforms; this is why we performed the first step of dividing the equation by "z."
So
or

Example
Verify the previous example by long division.
So
and the sequence f[k] is given by

Inverse Z Transform by Direct Inversion

This method requires the techniques of contour integration over a complex plane.  In particular
.
 The contour, G, must be in the functions region of convergence.  This technique makes use of Residue Theory and Complex Analysis and is beyond the scope of this document. 

Laplace transform


The Laplace transform is a powerful tool formulated to solve a wide variety ofinitial-value problems. The strategy is to transform the difficult differential equations into simple algebra problems where solutions can be easily obtained. One then applies the Inverse Laplace transform to retrieve the solutions of the original problems. This can be illustrated as follows:
Initial-Value Problems
ODE's or PDE's
Algebra Problems

Difficult

Very Easy
Solutions of
Initial-Value Problems
  
Solutions of
Algebra Problems
Definition of the Laplace Transform
For a function  defined on , its Laplace transform is denoted as  obtained by the following integral:
Laplace Transforms Related Calculator

where  is real and  is called the Laplace Transform Operator.
Conditions for the Existence 
of a Laplace Transform of f(t) = F(s)
1) is piecewise continuous on .
2) is of exponential order as . That is, there exist real constants , and  such that
for all .
Note that conditions 1 and 2 are sufficient, but not necessary, for  to exist.
Definition of the Inverse Laplace Transform
If the Laplace transform of  is , then the we say that the Inverse Laplace Transform of  is . Or,
Laplace Transforms Related Calculator

where  is called the Inverse Laplace Transform Operator.
Conditions for the Existence of an Inverse Laplace Transform of F(s) = f(t)
1).
2) is finite.